深入探讨:oracle中row_number() over()分析函数用法
发布时间:2020-10-19 07:44:11 所属栏目:Oracle 来源:互联网
导读:本篇文章是对oracle中row_number() over()分析函数的用法进行了详细的分析介绍,需要的朋友参考下
row_number()over(partition by col1 order by col2)表示根据col1分组,在分组内部根据col2排序,而此函数计算的值就表示每组内部排序后的顺序编号(组内连续的唯一的)。 语法格式: <FONT style="COLOR: #ff0000">1.row_number() over (order by col_1[,col_2 ...]) 作用:按照col_1[,col_2 ...]排序,返回排序后的结果集, 此用法有点像rownum,为每一行返回一个不相同的值: <div class="codetitle"><a style="CURSOR: pointer" data="12134" class="copybut" id="copybut12134" onclick="doCopy('code12134')"> 代码如下:<div class="codebody" id="code12134"> select rownum,ename,job, row_number() over (order by rownum) row_number from emp; ROWNUM ENAME JOB ROW_NUMBER ---------- ---------- --------- ---------- 1 SMITH CLERK 1 2 ALLEN SALESMAN 2 3 WARD SALESMAN 3 4 JONES MANAGER 4 5 MARTIN SALESMAN 5 6 BLAKE MANAGER 6 7 CLARK MANAGER 7 8 SCOTT ANALYST 8 9 KING PRESIDENT 9 10 TURNER SALESMAN 10 11 ADAMS CLERK 11 12 JAMES CLERK 12 13 FORD ANALYST 13 14 MILLER CLERK 14 如果没有partition by子句,结果集将是按照order by 指定的列进行排序; <div class="codetitle"><a style="CURSOR: pointer" data="3848" class="copybut" id="copybut3848" onclick="doCopy('code3848')"> 代码如下:<div class="codebody" id="code3848"> with row_number_test as( select 22 a,'twenty two' b from dual union all select 1,'one' from dual union all select 13,'thirteen' from dual union all select 5,'five' from dual union all select 4,'four' from dual) select a,b, row_number() over (order by b) from row_number_test order by a; 正如我们所期待的,row_number()返回按照b列排序的结果, 然后再按照a进行排序,才得到下面的结果: <div class="codetitle"><a style="CURSOR: pointer" data="81822" class="copybut" id="copybut81822" onclick="doCopy('code81822')"> 代码如下:<div class="codebody" id="code81822"> A B ROW_NUMBER()OVER(ORDERBYB) -- ---------- -------------------------- 1 one 3 4 four 2 5 five 1 13 thirteen 4 22 twenty two 5 <FONT style="COLOR: #ff0000">2.row_number() over (partition by col_n[,col_m ...] order by col_1[,col_2 ...]) 作用:先按照col_n[,col_m ...进行分组, 再在每个分组中按照col_1[,col_2 ...]进行排序(升序), 最后返回排好序后的结果集: <div class="codetitle"><a style="CURSOR: pointer" data="21343" class="copybut" id="copybut21343" onclick="doCopy('code21343')"> 代码如下:<div class="codebody" id="code21343"> with row_number_test as( select 22 a,'twenty two' b,'' c from dual union all select 1,'one','+' from dual union all select 13,'thirteen','' from dual union all select 5,'five','+' from dual union all select 4,'four','+' from dual) select a, row_number() over (partition by c order by b) row_number from row_number_test order by a; 这个例子中,我们先按照c列分组,分为2组('*'组,'+'组), 再按照每个小组的b列进行排序(按字符串首字母的ascii码排), 最后按照a列排序,得到下面的结果集: <div class="codetitle"><a style="CURSOR: pointer" data="2780" class="copybut" id="copybut2780" onclick="doCopy('code2780')"> 代码如下:<div class="codebody" id="code2780"> A B ROW_NUMBER -- ---------- ---------- 1 one 3 4 four 2 5 five 1 13 thirteen 1 22 twenty two (编辑:岳阳站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |